librelist archives

Fwd: Recoverging the tail to an URL rule

Fwd: Recoverging the tail to an URL rule by Juancarlo Añez
- Re: [flask] Fwd: Recoverging the tail to an URL rule by Oliver Berger
  - Re: [flask] Fwd: Recoverging the tail to an URL rule by Juancarlo Añez

Fwd: Recoverging the tail to an URL rule

From:: Juancarlo Añez
Date:: 2011-11-15 @ 16:31

Hello,

I want to build with Flask a simple application that will show in a nice
format the contents of a directory hierarchy filled with photographs.

The issue i'm having is that what needs to be done for each directory and
for each image is generic, but the application doesn't know what the
directory structure is beforehand.

Ideally, I would like to have RESTful URLs of the form:

http://mysiste.org/photos/1999/november/amsterdam/

or

http://mysiste.org/photos/1999/november/amsterdam/IMG2502.jpg


That could be handled by a single view function that understands that the
the trailing "1999/november/amsterdam/" part is a parameter, but I don't
know how to do that with simple @rule decorators.

Since I can examine the complete directory structure periodically, I
thought that I can do what I want by messing with the rules map
periodically, mapping the restful URLs to the same view functions. I just
think that being able to have a rule like "/photos/**" that gets the "**"
as a parameter would be much more pythonic.

Is there a way to do what I want with Flask?

Thanks in advance,

-- 
Juancarlo *Añez*




-- 
Juancarlo *Añez*

Re: [flask] Fwd: Recoverging the tail to an URL rule

From:: Oliver Berger
Date:: 2011-11-15 @ 21:45

I guess you want something like:

@app.route('/photos/<path:filepath>')
def show_file(filepath):
    pass


found here http://flask.pocoo.org/docs/api/#url-route-registrations

regards
Oliver


On 15.11.2011 17:31, Juancarlo Añez wrote:
> Hello,
> 
> I want to build with Flask a simple application that will show in a nice
> format the contents of a directory hierarchy filled with photographs.
> 
> The issue i'm having is that what needs to be done for each directory
> and for each image is generic, but the application doesn't know what the
> directory structure is beforehand.
> 
> Ideally, I would like to have RESTful URLs of the form:
> 
>     http://mysiste.org/photos/1999/november/amsterdam/
> 
>     or
> 
>     http://mysiste.org/photos/1999/november/amsterdam/IMG2502.jpg
> 
> 
> That could be handled by a single view function that understands that
> the the trailing "1999/november/amsterdam/" part is a parameter, but I
> don't know how to do that with simple @rule decorators.
> 
> Since I can examine the complete directory structure periodically, I
> thought that I can do what I want by messing with the rules map
> periodically, mapping the restful URLs to the same view functions. I
> just think that being able to have a rule like "/photos/**" that gets
> the "**" as a parameter would be much more pythonic.
> 
> Is there a way to do what I want with Flask?
> 
> Thanks in advance,
> 
> -- 
> Juancarlo *Añez*
> 
> 
> 
> 
> -- 
> Juancarlo *Añez*
>

Re: [flask] Fwd: Recoverging the tail to an URL rule

From:: Juancarlo Añez
Date:: 2011-11-16 @ 12:08

Oliver,

On Tue, Nov 15, 2011 at 17:15, Oliver Berger <oliver@digitalarchitekt.de>wrote:

> I guess you want something like:
>
> @app.route('/photos/<path:filepath>')
> def show_file(filepath):
>    pass
>

Exactly!

Thanks. I'll make some experiments with and without trailing slashes to see
what happens.

>
> found here http://flask.pocoo.org/docs/api/#url-route-registrations

May I say that I found the docs lacking in examples about this feature?

Regards,

-- 
Juancarlo *Añez*